CMA's shitposting thread
It doesn't matter, as such a "sphere" is coming straight from the warp and therefore heresy. Trying to understand makes you a heretic as well.
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Re: CMA's shitposting thread
Find me an equation that determines the sunspace distortion of a cinimon pop tart. Because cinimon has special sunspace powers.
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Re: CMA's shitposting thread
Pretty much, it's the volume of the sphere except for the infinitely thin 2D boundary around the sphere.prototype wrote:So you have a sphere, can be anywhere within that sphere, but cannot be on the surface?
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Re: CMA's shitposting thread
So in other words a useful equation for your everyday needs.
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Re: CMA's shitposting thread
Of course, I recite it every night before bed.Daynel wrote:So in other words a useful equation for your everyday needs.
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Re: CMA's shitposting thread
Considering this equation contains an undefined variable P I think its not as simple as "describing a ball", for the later it will be enough to only use P = 2 to get the norm of a given vector aka the distance to (0,0,0,...) which is BTW the center of this ball in R^n .
K lets begin with basics: R^n is the dimension we are working in: R^2 is 2D, R^3 is 3D, R^n is nD, in other words your "ball" (At this point it cant be a ball anymore) is a collection of all vectors in your dimension, in R^n, who’s distance from 0 point is below the radius or in other words all point inside your multi-dimensional "ball". All of that will be true if P=2, as for what P itself and its meaning you will have to explain me yourselves, for example if we are to use P = 1 this is not going to be a ball anymore for sure, many points that were supposed to be inside the ball with a radius of r are now left out, that is why this equasion cannot describe a ball by any means.
K lets begin with basics: R^n is the dimension we are working in: R^2 is 2D, R^3 is 3D, R^n is nD, in other words your "ball" (At this point it cant be a ball anymore) is a collection of all vectors in your dimension, in R^n, who’s distance from 0 point is below the radius or in other words all point inside your multi-dimensional "ball". All of that will be true if P=2, as for what P itself and its meaning you will have to explain me yourselves, for example if we are to use P = 1 this is not going to be a ball anymore for sure, many points that were supposed to be inside the ball with a radius of r are now left out, that is why this equasion cannot describe a ball by any means.
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Re: CMA's shitposting thread
Ehh, not sure what your argument is, but Ball is a technical term in this case, it could be a circle or a hypersphere or whatever. Read the Wikipedia article, it explains it better than I can.Iv121 wrote:Considering this equation contains an undefined variable P I think its not as simple as "describing a ball", for the later it will be enough to only use P = 2 to get the norm of a given vector aka the distance to (0,0,0,...) which is BTW the center of this ball in R^n .
K lets begin with basics: R^n is the dimension we are working in: R^2 is 2D, R^3 is 3D, R^n is nD, in other words your "ball" (At this point it cant be a ball anymore) is a collection of all vectors in your dimension, in R^n, who’s distance from 0 point is below the radius or in other words all point inside your multi-dimensional "ball". All of that will be true if P=2, as for what P itself and its meaning you will have to explain me yourselves, for example if we are to use P = 1 this is not going to be a ball anymore for sure, many points that were supposed to be inside the ball with a radius of r are now left out, that is why this equasion cannot describe a ball by any means.
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Re: CMA's shitposting thread
>You will never die in the Crusade against Bolshevism
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Re: CMA's shitposting thread
No it was you who didn’t get my point, as I wrote above the equation doesn't describe a ball in any dimension due to the presence of P, if P = 2 only then it describes a "ball" in dimension n.Captain Obvious wrote: Ehh, not sure what your argument is, but Ball is a technical term in this case, it could be a circle or a hypersphere or whatever. Read the Wikipedia article, it explains it better than I can.
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Re: CMA's shitposting thread
Iv.
what r u doing
stahp
start something with anyone but cma. won't end well for you.
what r u doing
stahp
start something with anyone but cma. won't end well for you.

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Re: CMA's shitposting thread
Whelp, might as well start making popcorn.
Who wants some?
Who wants some?
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Re: CMA's shitposting thread
I'll get some Coke and a shotgun in case things get out of hand.

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Re: CMA's shitposting thread
Cocaine and shotguns. Shotgun shells FILLED with cocaine!
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Re: CMA's shitposting thread
catsonmeth wrote:Cocaine and shotguns. Shotgun shells FILLED with cocaine!

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Mistake Not... wrote: This isn't rocket science, *!

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Re: CMA's shitposting thread
That's what I said.Iv121 wrote:No it was you who didn’t get my pointCaptain Obvious wrote: Ehh, not sure what your argument is, but Ball is a technical term in this case, it could be a circle or a hypersphere or whatever. Read the Wikipedia article, it explains it better than I can.
It's not describing a ball, it's describing a Ball, read the wikipedia article. Brb actually understanding the equation.Iv121 wrote: , as I wrote above the equation doesn't describe a ball in any dimension due to the presence of P, if P = 2 only then it describes a "ball" in dimension n.
Edit: Y'all put the post in shitposting in my shitposting thread.
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